To me, your result is useless and frustrating. We still don't know what the IC is or does. It should take only a few minutes to trace the circuit around those 6 components and to measure the voltages on all the pins. That would tell us everything we need to know. It's quite possible that the IC is an e-fuse or load switch, in which case it could be bypassed with a link instead of sacrificing a donor. The part on the left is probably a capacitor (according to the voltages), although its colour is more like an inductor.
By the way, I found this example of the Dunning-Kruger Effect:
https://www.youtube.com/watch?v=QfVV68bVg1Y
This bright spark repairs laptop motherboards for a living but doesn't know what a fuse is. The fuse lights up his thermal camera, so he thinks that this mystery component is shorted. Sure enough, when he measures the fuse with his multimeter, it does indeed test as 0 ohms. Therefore, he thinks it's faulty. After removing it with his hot air station, he tests the pads on the PCB and the short is gone (obviously), but he doesn't think to test for shorts between the output of the fuse and ground. Anyone who repairs motherboards for a living should recognise the fuse because the same components are used to protect HMDI and USB and PS/2 mouse/keyboard ports. They all have the tell-tale semicircular cutouts at each end. Moreover, any real component-level tech knows that when something heats up, you should check for shorts downstream. He now replaces the fuse with a part cannibalised from a donor (presumably at the ciustomer's expense) and miraculously the device starts working. I can only assume that the old fuse was tired, or, more likely, the heat cleared the short in an adjacent ceramic capacitor.
By the way, the fuse is a polyswitch or resettable PPTC fuse.
https://www.google.com/search?imgtype=photo&q=polyswitch+OR+PPTC+OR+polyfuse&tbs=isz:m&udm=2
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